u^2+11u+11=0

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Solution for u^2+11u+11=0 equation: 



u^2+11u+11=0

a = 1; b = 11; c = +11;
Δ = b2-4ac
Δ = 112-4·1·11
Δ = 77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{77}}{2*1}=\frac{-11-\sqrt{77}}{2}
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{77}}{2*1}=\frac{-11+\sqrt{77}}{2}
$

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